The Lagrange point L1
between the Earth and the Moon
On a line connecting the Earth and the Moon there are three points where a small body may exist in an unstable equilibrium if it has a velocity giving it the same period as the Moon. In these points, the sum of the gravitational forces from the Earth and the Moon supplies just the centripetal force necessary for a circular orbit with the period of the Moon. These points are called Lagrange points. Also see the simulation ("The Moon and L4").
We assume that the Moon travels in a circular orbit at the distance a from the Earth. Let the distance from the Earth to L1 be x and put z = x/a. The ratio between the masses of the Moon and the Earth is k = 0.01229. One can show that z is a solution of the equation
(1)
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This 5. degree equation may be solved on a graphical calculator. We find z = 0.849, giving x = 326054 km.
Formulas for calculating the relevant parameters of the Earth and the Moon are derived in the simulation "Orbit of the Moon". Using one of these formulas gives the Moon's period in our assumed circular orbit equal to T = 2352900 s. We want Body1 to travel in a circular orbit with this period about the center of mass. The distance from L1 to the center of mass is 326054 km - 4662 km = 321392 km. The velocity of Body1 should be
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